The rate constant for the decomposition of acetaldehyde, CH₃CHO, to methane, CH₄, and carbon monoxide, CO, in the gas phase is 1.32 ✕ 10⁻² L/mol/s at 707 K and 3.20 L/mol/s at 851 K. Determine the activation energy (in kJ/mol) for this decomposition.

The correct answer is 190.74 KJ/mol

Explanation:

In order to determine the activation energy of a reaction (Ea) from two reaction rates (k1 and k2) at two different temperatures (T1 and T2), we have to use the following equation:

ln (k2/k1)= Ea/R x (1/T1 - 1/T2)

Where R is the gas constant (8.3145 J/mol.K).

We have: k1= 1.32 x 10⁻² L/mol/s ; T1= 707 K

               k2= 3.20 L/mol/s ; T2= 851 K

We introduce the data in the equation and determine Ea:

ln (3.20 L/mol/s/1.32 x 10⁻² L/mol/s) = Ea/(8.3145 J/K.mol) x ( (1/707 K) - (1/851 K))

⇒Ea = ln (3.20 L/mol/s/1.32 x 10⁻² L/mol/s)/ ( (1/707 K) - (1/851 K)) x (8.3145 J/K.mol)

⇒Ea = 190,743 J/mol

We divide by 1000 to obtain Ea in KJ/mol: 190.74 KJ/mol

the link still does not work even when adding it to the url bar

explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.