Use the library and other reference materials to research the discovery of radioactivity and its current applications. Then, write a 500 word report on what you have learned. Be sure to include the contributions of French chemists Marie Curie and Pierre Curie and the medical uses of radiation.

Henri Becquerel was a French physicist who in 1896 discovered a new property of matter (which was later called radioactivity). This was accidentally observed when Becquerel found out that uranium salt was spontaneously emitting some kind of rays that went through different substances and were able to veil even a photographic film.  Then Marie Curie and her husband Pierre Curie carried out more experiments to study, in a quantitative way, the radiation emitted by the salts Becquerel studied cualitatively, and other salts that contained uranium. During this process they found other radioactive substances, such as: thorium, polonium and radium.These radioactive isotopes have proven particularly effective as tracers in certain diagnostic procedures. As radioisotopes are identical chemically with stable isotopes of the same element, they can take the place of the latter in physiological processes. Moreover, because of their radioactivity, they can be readily traced even in minute quantities with such detection devices as gamma-ray spectrometers and proportional counters. Though many radioisotopes are used as tracers, iodine-131, phosphorus-32, and technetium-99m are among the most important. Physicians employ iodine-131 to determine cardiac output, plasma volume, and fat metabolism and particularly to measure the activity of the thyroid gland where this isotope accumulates. Phosphorus-32 is useful in the identification of malignant tumours because cancerous cells tend to accumulate phosphates more than normal cells do. Technetium-99m, used with radiographic scanning devices, is valuable for studying the anatomic structure of organs.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally