The bond enthalpy of the oxygen-oxygen bond in O2 is 498 kJ/mol. Based on the enthalpy of the reaction represented above, what is the average bond enthalpy, in kJ/mol, of an oxygen-oxygen bond in O3?

The given question is incomplete. The complete question is as follows.

The enthalpy of formation of ozone is 142.7 kJ / mol. The bond energy of is 498 kJ / mol. What is the average O=O bond energy of the bent ozone molecule O=O=O?

Explanation:

The given reaction is as follows.

The value of for 2 moles of ozone is = 285.4 kJ/mol.

So, in this reaction three O=O bonds are broken down and four O-O bonds of ozone are formed.

Expression for the enthalpy of reaction is as follows.

       285.4 kJ/mol =

       285.4 kJ/mol =

           -1208.6 kJ/mol =

                = 604.3 kJ/mol

Now, the average bond enthalpy of O-O bond in is as follows.

                          = kJ/mol

                          = 201.43 kJ/mol

Thus, we can conclude that for the given reaction average bond enthalpy of an oxygen-oxygen bond in is 201.43 kJ/mol.

idk what is it? is this a question that you know the answer or u dont