If 34.5 g of Copper reacts with 70.2 g of silver nitrate, according to the following
reaction, what is the maximum number of grams of silver that can be

Cu + _ Ag(NO3) → Cu(NO3)2 + Ag

44. 6gAg can be produced

Explanation:

Hello,

In this case, the first step is to write the balanced chemical reaction:

Next, we find the limiting reactant, for that reason we compute the moles of copper that are available and the moles that will react with 70.2 g of silver nitrate as shown below:

In such a way, since there are more available moles of copper, it is in excess, so the silver nitrate is the limiting reactant, this, the maximum grams of silver result:

Best regards.

the correct answer to this question is 2