How many grams of calcium sulfite are produced daily by this power plant?

Explanation:

Explanation:

S

O

2

(

g

)

+

C

a

O

(

s

)

→

C

a

S

O

3

(

s

)

1 US ton

=

907.19

⋅

k

g

Mass of coal(kg)

=

2000

⋅

ton

×

907

⋅

k

g

⋅

ton

−

1

=

1.814

×

10

6

⋅

k

g

.

Mass of sulfur

=

1.814

×

10

6

⋅

k

g

×

2.5

%

=

45

,

350

⋅

k

g

Moles of sulfur

=

45

,

350

⋅

k

g

×

10

3

⋅

g

⋅

k

g

−

1

32.06

⋅

g

⋅

m

o

l

−

1

=

1.41

×

10

6

⋅

m

o

l

.

And thus we may have  

1.41

×

10

6

⋅

m

o

l

S

O

2

produced during the daily operation.

Given the equivalence of sulfur dioxide and calcium oxide in the first equation, clearly we need  

1.41

×

10

6

⋅

m

o

l

C

a

O

to produce  

1.41

×

10

6

⋅

m

o

l

C

a

S

O

3

.

Mass of calcium sulfite produced daily

=

1.41

×

10

6

⋅

m

o

l

×

120.17

⋅

g

⋅

m

o

l

−

1

=

1.70

×

10

8

⋅

g

=

1.70

×

10

5

⋅

k

g

.

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.