What is the temperature of 0.52 mol of gas at a pressure 131.722kpa and a volume of 11.8l

The temperatue is 0.4 K.

Explanation:

As per the kinetic theory of gases, the product of pressure with volume will be equal to the product of concentration and volume. This law is formed by combination of Charle's law and Boyle's law.

Here n = 0.52 mo; P = 131.722 kpa, V = 11.81.

PV = nRT

Here n is the mole concentration, P is the pressure and V is the volume.

(131.722× 10³×11.8)=(0.52×8.314×T)

1.554 = 4.32 T

T = 1.554/4.32=0.4 K

T = 0.4 K.

Thus, the temperatue is 0.4 K.

the answer is b. dilution