When 0.40 mole of SO2 and 0.60 mole of O2 are placed in an evacuated 1.00-liter flask, the reaction represented above occurs. After the reactants and the product reach equilibrium and the initial temperature is restored, the flask is found to contain 0.30 mole of SO3. Based on these results, the equilibrium constant, Kc for the reaction is.

kc = 20

Explanation:

The reaction is:

2SO₂ + O₂ ⇄ 2SO₃

Where kc is defined as:

kc = SO₃² / O₂×SO₂² (1)

The initial moles are 0,40 for SO₂ and 0,60 moles for O₂

The moles in equilibrium must be:

SO₂: 0,40 - 2x

O₂: 0,60 - x

SO₃: 2x = 0,30; x = 0,15

Replacing:

SO₂: 0,40 - 2×0,15 = 0,10 moles

O₂: 0,60 - 0,15 = 0,45 moles

Replacing these values in (1):

kc = 0,30² / 0,45×0,10²

kc = 20

I hope it helps!

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

what are the two models

explanation: