As an athlete exercises, sweat is produced and evaporated to help maintain a proper body temperature. On average, an athlete loses approximately 307 g of sweat during an hour of exercise. How much energy is needed to evaporate the sweat that is produced? The heat of vaporization for water is 2257J/g. energy required:

For the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

Explanation:

We are given:

Heat of vaporization for water = 2257 J/g

Amount of sweat lost = 307 grams

Applying unitary method:

For 1 g of sweat lost, the energy required is 2257 Joules

So, for 307 grams of sweat lost, the energy required will be =

Hence, for the given amount of sweat lost, the amount of energy required will be 692,899 Joules.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.