Ammonium carbonate decomposes upon heating according to the following balanced equation:
(NH4)2CO3(s)?2NH3(g)+CO2(g)+H2O(g)< br />
Calculate the total volume of gas produced at 24.0?C and 1.05atm by the complete decomposition of 11.9g of ammonium carbonate

Answer : The total volume of gas produced are, 11.5 L

Explanation :

First we have to calculate the moles of ammonium carbonate.

Molar mass of = 96.094 g/mol

Now we have to calculate the moles of total gas.

The given balanced chemical reaction is:

From the balanced chemical reaction we conclude that,

As, 1 mole of react to give 4 mole of gas

So, 0.124 mole of react to give mole of gas

Now we have to calculate the volume of gas.

Using ideal gas equation:

where,

P = Pressure of gas = 1.05 atm

V = Volume of gas = ?

n = number of moles = 0.496 mole

R = Gas constant =

T = Temperature of gas =

Putting values in above equation, we get:

Thus, the total volume of gas produced are, 11.5 L

- decrease the number of plants and animals living in the water.

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally