Tion 1 of 20
1.1.25 X 10^45 molecules of chlorine gas react with sodium to form how many grams of
sodium chloride? 2 Na + Cl2 --> 2 Naci
1.25 grams
1.20 X 10^23 grams
2.41 X 10^23 grams
none of these
Why

The mass of NaCl produced is 1.2 * 10^23 grams

Explanation:

Step 1: Data given

Number of molecules of Cl2 - gas = 1.25 * 10^45 molecules

Number of Avogadro = 6.022 * 10^23

Step 2: The balanced equation

2 Na + Cl2 → 2 NaCl

Step 3: Calculate moles of Cl2

Moles Cl2 = 1.25 *10^45 / 6.022*10^23

Moles Cl2 = 2.1 *10^21 moles

Step 4: Calculate moles NaCl

For 2.1 *10^21 moles Na we'll have 2.1*10^21 moles NaCl

Step 5: Calculate mass NaCl

Mass NaCl =  moles NaCl * molar mass NaCl

Mass NaCl = 2.1*10^21 moles * 58.44 g/mol

Mass NaCl = 1.2 *10^23 grams

The mass of NaCl produced is 1.2 * 10^23 grams

the increase of protons   hope this

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