A 6.55 g sample of aniline (C_{6}H_{5}H_{2}, molar mass = 93.13 g/mol) was combusted in a bomb calorimeter. If the temperature rose by 32.9°C, use the information below to determine the heat capacity of the calorimeter.

Heat Capacity of calorimeter is 6.842 kJ/°C

Explanation:

4 C6H5NH2(l) + 35 O2(g) → 24 CO2(g) + 14 H2O(g) + 4 NO2(g)

ΔH°rxn = -1.28 x 10⁴ kJ

4 moles of aniline gives 12800 kJ of heat,

1 mole of aniline will give 12800/4 kJ amount of heat = 3200 kJ

ΔH°rxn for 1 mole of aniline = -3200 kJ

1 mole of aniline weighs 93.13 g/mol

6.55 g of aniline has 6.55/93.13 moles = 0.0703 moles

And this would give off 0.0703 × 3200J amount of heat off

0.0703 × 3200 = 225.1 kJ.

Heat lost by aniline = Heat gained by calorimeter,

Heat lost by aniline = 225.1 kJ

Heat gained by calorimeter = C ΔT = C (32.9)

225.1 = C (32.9)

C = 6.842 kJ/°C

here's the link to your question!

explanation:

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j