K + H2O --> KOH + H2

1. How many grams of KOH are produced if 224 g of H2O are used?
2. How many moles of K are used if 20 moles of H2O react?
3. How many grams of H2O are used if 3678 grams of H2 are produced?

1. 696.9g of KOH

2. 20moles of K

3. 66204g of H2O

Explanation:

First, we need to generate a balanced equation for the reaction. This is illustrated below:

2K + 2H2O —> 2KOH + H2

Next, we'll find the molar mass and mass of the reactants and products as shown below:

Molar Mass of K = 39g/mol

Mass of K from the balanced equation = 2x39 = 78g

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of H2O from the balanced equation = 18 x 2 = 36g

Molar Mass of KOH = 39 + 16 + 1 = 56g/mol

Mass of KOH from the balanced equation = 2 x 56 = 112g

Molar Mass of H2 = 2x1 = 2g/mol

1. 2K + 2H2O —> 2KOH + H2

From the balanced equation,

36g of H20 produced 112g of KOH.

Therefore, 224g of H2O will produce = (224 x 112)/36 = 696.9g of KOH

2. 2K + 2H2O —> 2KOH + H2

From the balanced equation,

2moles of K required 2moles of H2O.

Therefore, Xmol of K will require 20moles of H2O i.e

Xmol of K = (20 x 2) / 2 = 20moles

3. 2K + 2H2O —> 2KOH + H2

From the balanced equation,

36g of H2O produced 2g of H2.

Therefore,

Xg of H2O will produce 3678g of H2 i.e

Xg of H2O = (3678 x 36)/2 = 66204g

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water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.