A student is studying the equilibrium described by the equation: blue + 4 Br (aqjs green + 6H20(1)

a) The system is at equilibrium and has a blue color. The student added several crystals of sodium bromide (NaBr) to this blue equilibrium solution. Predict happened in the reaction mixture and explain why.
b) The student placed the green equilibrium solution in an ice bath. After a short time, the solution turned blue. What does i tell you about the thermochemical character of the forward reaction? Explain your answer.

This is the correct equilibrium represented in the question

Blue + 4 Br- (aq) <---> green + 6H2O (l)

Addition of NaBr supplied the Br- ions which moved the equilibrium position towards the right hand side. The forward reaction is endothermic hence its rate decreases when the reaction mixture is placed in an ice bath.

Explanation:

Blue + 4 Br- (aq) <---> green + 6H2O (l)

Looking at the equilibrium represented above, addition of Br- moves the equilibrium towards the right hand side, that is, the green colour. Addition of NaBr increases the Br- concentration and drives the forward reaction hence the equilibrium position shifts towards the right hand side. The fact that the solution turns blue when placed in ice bath reveals that the forward reaction is endothermic. Decreasing the temperature shifts the equilibrium position towards the left hence the resurgence of the blue colour.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.