Consider the first-order reaction described by the equation Cyclopropane gas isomerizes to propene gas. At a certain temperature, the rate constant for this reaction is 5.05 × 10 − 4 s − 1 . Calculate the half-life of cyclopropane at this temperature. t 1 / 2 = s Given an initial cyclopropane concentration of 0.00670 M , calculate the concentration of cyclopropane that remains after 2.00 hours. concentration.

The half-life would be 1372 seconds.

The concentration remains after 2 hours is 0.000177 M.

Explanation:

Given the initial concentration of was .

And the rate constant is

We need to calculate the half-life and the concentration remains after 2 hours.

First, we will use the formula of half-life of the first order reaction.

So, half-life would be 1372 seconds.

Now, we will find its concentration after 2 hours. That means

Use the equation

So, the concentration remains after 2 hours is 0.000177 M.

b. acid is the correct answer @jayxboof all social media

acid : acids are those which accepts an electron-pairs.

base : bases are those which donates ab electron-pairs.

alkali : it is a base that dissolves in water. it is basically a base and the ph greater than 7.

hydroxide ion : it is a poly-atomic ion which is negatively charged.

hypostyle hall;