Answers: 3
Chemistry, 22.06.2019 04:00
Two nitro no2 groups are chemically bonded to a patch of surface. they can't move to another location on the surface, but they can rotate (see sketch at right). it turns out that the amount of rotational kinetic energy each no2 group can have is required to be a multiple of ε, where =ε×1.010−24 j. in other words, each no2 group could have ε of rotational kinetic energy, or 2ε, or 3ε, and so forth — but it cannot have just any old amount of rotational kinetic energy. suppose the total rotational kinetic energy in this system is initially known to be 32ε. then, some heat is removed from the system, and the total rotational kinetic energy falls to 18ε. calculate the change in entropy. round your answer to 3 significant digits, and be sure it has the correct unit symbol.
Answers: 2
Chemistry, 22.06.2019 05:30
What royal scientist used the 29th day of frozen vapor to encounter elements for mastering new culinary creations?
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Chemistry, 22.06.2019 19:00
Which is the solubility product expression for caf2(s)?  [ca2+]/[f–]2  [ca2+][f2–]  [ca]+[f]2  [ca2+][f–]2
Answers: 3
Chemistry, 23.06.2019 05:00
If 15 drops of ethanol from a medicine dropper weigh 0.60g, how many drops does it takes from a dropper to dispense 1.0ml of ethanol? density of ethanol is ethanol is 0.80g/ml.
Answers: 2
The pH of a 0.25 M (aq) solution of hydrofluoric acid, HF, at 25C is 2.03. What is the value of Ka f...
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