Magnesium hydroxide is 54.87% oxygen by mass. how many grams of oxygen are in 175 g sample of the compound

The mass of oxygen in 175 g of Mg(OH)₂ having 54.87% of oxygen is 96.0225 g.

Magnesium hydroxide has 54.87% of oxygen by mass. The chemical formula of  Magnesium hydroxide can be represented below

Atomic mass of Mg = 24g

Atomic mass of Oxygen = 16g

Atomic mass of  = hydrogen = 1 g

Molar mass number of Mg(OH)₂ = 24 + 16(2) + 2 = 58 g

Oxygen is 54.87% by mass in the compound and the mass of the compound is 175 g. Therefore, the mass of oxygen can be calculated below:

mass of oxygen = 54.87 / 100 × 175

mass of oxygen =  9602.25 / 100 = 96.0225 grams

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96 g of O

Explanation:

Mg(OH)₂ → Magnesium hydroxide

Molar mass → 24.3g/mol . 1 + 16g/mol . 2 + 1g/mol . 2 = 58.3 g/mol

We determine the moles of hydroxide → 175 g . 1mol/58.3g = 3 moles

Let's make some rule of three:

In 100 g of compound we have 54.87 g of O

In 58.3 g of compound we may have (58.3 . 54.87) / 100 = 32 g

So, 1 mol of hydroxide has 32 g of oxygen

3 moles of hyroxide may have (3 .32)/1 = 96 g of O

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explanation:

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-