Calculate the molality (m) of an aqueous solution of HCl which is 36.71% HCl by mass and has a density of 1.076 g/mL.

15.9 mol/kg is the molality for the solution

Explanation:

36.71% means that 36.71 g of solute are contained in 100g of solution

36.71 g → mass of solute

100 g → mass of solution (mass of solute + mass of solvent)

Mass of solvent → 100 g - 36.71 g = 63.29 g

Molality → moles of solute in 1kg of solent

We convert the mass of solute to mol → 36.71 g . 1mol/36.45 g =1.007 mol

We convert the mass of solvent from g to kg → 63.29 g . 1kg/1000g = 0.06329 kg

1.007 mol /0.06329 kg → molality → 15.9 m

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