When a strong acid-strong base neutralization reaction is also a limiting reactant situation, the leftover reactant will determine your final solution pH. Remember that a limiting reactant indicates that you will run out of one reactant first.

Considering the reaction of potassium hydroxide and hydrobromic acid, notice that if you have excess acid leftover it would react with water to produce H3O+ ions in solution: HBr + H2O → Br- + H3O+

If you have excess base left over, it will dissociate in water to produce OH- ions: KOH → K+ + OH-

You mix 2 moles of HBr with 3 moles of KOH in enough water to make 1 L of solution. What is the pH of your final solution?

it is called acid bonding

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

the maximum mass of nh3 is nh3 in grams