Calculate the pH of a solution prepared by dissolving 0.150 mol of benzoic acid and 0.300 mol of sodium benzoate in water sufficient to yield 1.00 L of solution. The Ka of benzoic acid is 6.30 × 10-5.

Answer : The pH of a solution is, 4.50

Explanation : Given,

Concentration of benzoic acid (Acid) = 0.150 M

Concentration of sodium benzoate (salt) = 0.300 M

First we have to calculate the value of .

The expression used for the calculation of is,

Now put the value of in this expression, we get:

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

Now put all the given values in this expression, we get:

Thus, the pH of a solution is, 4.50

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