The value of for the equilibrium H2 (g) + I2(g) 2 HI (g) is 794 at 25 °C. What is the value of for the equilibrium below? 1/2 H2 (g) + 1/2 I2(g) HI (g)

The value of equilibrium constant for given reaction will be 28.18.

Explanation:

The value of equilibrium constant = K = 794

The expression of an equilibrium will be given by ;

The value of equilibrium constant for above reaction= K' = ?

The expression of an equilibrium will be given by ;

Squaring both sides:

The value of equilibrium constant for given reaction will be 28.18.

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation:

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.