How many moles of O2 gas are there in a 1.0 L container which contains 0.12 atm of O2 gas at 25 ºC? (The correctly abbreviated unit in the correct case is required for this question.)

The number of moles of oxygen gas in the container is 0.0049 moles

Explanation:

To calculate the moles of oxygen gas, we use the equation given by ideal gas which follows:

where,

P = pressure of the gas = 0.12 atm

V = Volume of the gas = 1.0 L

T = Temperature of the gas =

R = Gas constant =

n = number of moles of oxygen gas = ?

Putting values in above equation, we get:

Hence, the number of moles of oxygen gas in the container is 0.0049 moles

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o