The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of this sample?

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

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explanation:

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.