Which gas is formed when h2co3 is produced in an aqueous solution

Carbon dioxide (CO₂)

Explanation:

Carbonic acid decomposes to release water and carbon dioxide:

H₂CO₃ →  H₂O + CO₂

In an aqueous solution, it has this two equilibriums where it release 2 protons. It is a weak acid:

H₂CO₃  + H₂O ⇄ HCO₃⁻  +  H₃O⁺         Ka₁

HCO₃⁻  +  H₂O ⇄  CO₃⁻²  +  H₃O⁺         Ka₂

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g