An unknown salt is either NaF, NaCl, or NaOCl. When 0.050 mol of the salt is dissolved in water to form 0.500 L of solution, the pH of the solution is 8.08. Part A What is the identity of the salt?

The unknown salt is NaF

Explanation:

To calculate the molarity of solution, we use the equation:

Moles of salt = 0.050 moles

Volume of solution = 0.500 L

Putting values in above equation, we get:

pH + pOH = 14

We are given:

pH = 8.08

Putting values in above equation, we get:

The unknown salt given are formed by the combination of weak acid and strong acid which is NaOH

The chemical equation for the hydrolysis of ions follows:

Initial:              0.1

At eqllm:        0.1-x                           x              x

Concentration of

The expression of for above equation follows:

Putting values in above expression, we get:

where,

= Ionic product of water =

= Acid dissociation constant

= Base dissociation constant =

Putting values in above equation, we get:

We know that:

So, the calculated is approximately equal to the of HF

Hence, the unknown salt is NaF

the answer to your question is c.

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