C5H12 8 O2 → 5 CO2 + 6H20
How many grams of carbon dioxide will form from the combustion 320.0 grams of
C5H12 with excess oxygen?

976.8 g

Explanation:

C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂0 (1)

number of moles of reaction 1 can be shown as;

1 : 8 → 5 : 6

thus, 5 moles of CO₂ will form from the combustion of 1 mole of C₅H₁₂

molecular weight of CO₂ = 44 g/mol

molecular weight of C₅H₁₂ = 72 g/mol

mass of C₅H₁₂ = 320 g

number of moles of C₅H₁₂ = mass ÷ molecular weight = 320 / 72 = 4.44 moles

thus, number of moles of CO₂ formed = 5 * 4.44 = 22.2 moles

mass of CO₂ formed = 22.2* 44 = 976.8 g

yes definetly because you are using energy

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.