Answers: 2
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0524/9978/6d953.png)
= rate constant at 271 K
= rate constant at 281 K = 
= activation energy for the reaction = ?
= initial temperature = 271 K
= final temperature = 281 K![\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{271K}-\frac{1}{281K}]](/tpl/images/0524/9978/ceafb.png)
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