The volume of a weather balloon is 200.0 L and its internal pressure is 1.17 atm when it is launched at 20 °C. The balloon rises to an altitude in the stratosphere where its internal pressure is 63 mmHg and the temperature is 210 K. What is the volume (in L) of the balloon then?

2022 L

Explanation:

Ideal gas laws will work for gas in the balloon

The general gas law is for a gas at two arbitrary states 1 and 2 is given by

(P₁ V₁)/T₁ = (P₂ V₂)/T₂

P₁ = 1.17 atm

V₁ = 200.0 L

T₁ = 20°C = 293.15 K

P₂ = 63 mmHg = 0.0829 atm

V₂ = ?

T₂ = 210 K

(1.17 × 200)/293.15 = (0.0829 × V₂)/210

V₂ = (210 × 1.17 × 200)/(293.15 × 0.0829)

V₂ = 2022 L

adding or remove a gaseous reactant or product changes the concentrations. if the concentration of reactant or product is increased, the system will shift away from the side in which concentration was increased (i.e. if the concentration of reactants is increased, the system will shift toward the products. if more products are added, the system will shift to form more reactants). conversely, if the concentration of reactant or product is decreased, the system will shift toward the side in which concentration was decreased (i.e. if reactants are removed, the system will shift to form more reactants. if the concentration of products is decreased, the equilibrium will shift toward the products).

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