Calcium nitrate will react with ammonium chloride at slightly elevated temperatures, as represented in the equation below. Ca(NO3)2(s) + 2NH4Cl(s) → 2N2O(g) + CaCl2(s) + 4H2O(g) What is the maximum volume of N2O at STP that could be produced using a 5.20-mol sample of each reactant?

Answer : The maximum volume of  at STP produced is, 116.48 L

Explanation :

First we have to calculate the limiting and excess reagent.

The given balanced chemical reaction is:

From the balanced reaction we conclude that

As, 2 mole of react with 1 mole of

So, 5.20 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 2 mole of react to give 2 mole of

So, 5.20 mole of react to give 5.20 mole of

Now we have to calculate the volume of

As we know that, 1 mole of substance occupies 22.4 L volume of gas at STP.

As, 1 mole of occupies 22.4 L volume of gas

So, 5.20 mole of occupies volume of gas

Thus, the maximum volume of  at STP produced is, 116.48 L