Imagine you have a 1.0 mL water sample containing 0.10 M hydrochloric acid, HCl. You want to get it to a safe pH of 6. How much water do you need to add

See explanation below

Explanation:

In this case, HCl is a strong acid, therefore, it dissociates completely in solution.

To know the quantity of water we need to add, we first need to know the concentration of the acid with pH = 6:

[H⁺] = antlog(-pH)

[H⁺] = antlog(-6) = 1x10⁻⁶ M

This means that the concentration is being diluted.

Now, even if we add great quantities of water, and the concentration and volume change, there is one time that do not change despite the quantity of water added; this is the moles. So, all we have to do, is calculate the moles of the acid in the 1 mL of water, and then, the volume of the acid when it's dilluted:

moles HCl = 0.1 * (1/1000) = 1x10⁻⁴ moles

Now that we have the moles, we can calculate the volume which the acid with the lowest concentration has:

V = mol/M

V = 1x10⁻⁴ / 1x10⁻⁶

V = 100 L

This means that we need to add 99.999 mL of water

the correct answer is:

a. formation of precipitation