Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 Pb(ClO3)2 with aqueous NaI . NaI. Include phases. chemical equation: What mass of precipitate will form if 1.50 L 1.50 L of highly concentrated Pb ( ClO 3 ) 2 Pb(ClO3)2 is mixed with 0.400 L 0.130 M NaI 0.400 L 0.130 M NaI ? Assume the reaction goes to completion

The mass of precipitate (lead (II) iodide) that will form is 119.89 grams

Explanation:

To calculate the number of moles for given molarity, we use the equation:

Molarity of NaI solution = 0.130 M

Volume of solution = 0.400 L

Putting values in above equation, we get:

The balanced chemical equation for the reaction of lead chlorate and sodium iodide follows:

The precipitate (insoluble salt) formed is lead (II) iodide

By Stoichiometry of the reaction:

2 moles of NaI produces 1 mole of lead (II) iodide

So, 0.52 moles of NaI will produce = of lead (II) iodide

To calculate the number of moles, we use the equation:

Moles of lead (II) iodide = 0.26 moles

Molar mass of lead (II) iodide = 461.1 g/mol

Putting values in above equation, we get:

Hence, the mass of precipitate (lead (II) iodide) that will form is 119.89 grams

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

it means there are 3 atoms of oxygen