At what temperature would a gas have a volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28 C

Answer : The initial temperature of gas would be, 269.7 K

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 0.723 atm

= final pressure of gas = 0.612 atm

= initial volume of gas = 13.5 L

= final volume of gas = 17.8 L

= initial temperature of gas = ?

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus, the initial temperature of gas would be, 269.7 K

i'm pretty sure its b i might be wrong though!

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error