Calculate the change in entropy that occurs in the system when 2.70 mole of diethyl ether (C4H6O) condenses from a gas to a liquid at its normal boiling point (34.6∘C). ΔHvap = 26.5 kJ/mol

The change in entropy that occurred in the system is 232.6 J/K.

The given parameters:

The energy released in the process is calculated as follows;

The change in entropy that occurred in the system is calculated as follows;

Thus, the change in entropy that occurred in the system is 232.6 J/K.

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233 Joules/K

Explanation:

∆H= 26.5KJmol-1

Kelvin temperature = 34.6 + 273 = 307.6 K

No of moles= 2.7 moles

2.70 mole x 26.5 kJ/mole = 71.55kilojoules

∆S=71.55 kilojoules / 307.6 K = 0.233 kilojoules/ K

Convert to JK-1

0.233 kilojoules/ K x 1000 Joules/kilojoule = 233 Joules/K

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answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.