How many liters of a 6.0M solution Fe(SCN)2 are needed to prepare 2.0L of a 0.75M solution?

We need 0.25 L of the 6.0 M solution

Explanation:

Step 1: Data given

Molarity of the Fe(SCN)2 solution = 6.0 M

Volume of the 0.75 M solution = 2.0 L

Step 2: Calculate volume

C1*V1 = C2*V2

⇒ with C1 = the initial concentration = 6.0 M

⇒ with V1 = the initial volume = TO BE DETERMINED

⇒ with C2 = the new concentration = 0.75 M

⇒ with V2 = the new volume = 2.0 L

6.0M * V1 = 0.75M * 2.0L

V1 = (0.75 M * 2.0L) / 6.0 M

V1 = 0.25 L

We need 0.25 L of the 6.0 M solution