Chemistry, 27.02.2020 05:42 lexxa58

A 20.00 mL Ba ( OH ) 2 solution of unknown concentration was neutralized by the addition of 42.50 mL of a 0.1255 M HCl solution. Write the balanced molecular equation for the neutralization reaction between HCl and Ba ( OH ) 2 in aqueous solution. Include physical states. molecular equation: Ba^{2+}(aq) +2OH^{-}(aq) +H^{+}(aq) +Cl^{-}(aq)<=>H_{2}O(l) +Ba^{2+}(aq) +Cl^{-}(aq) Ba 2 + ( aq ) + 2 OH − ( aq ) + H + ( aq ) + Cl − ( aq ) − ⇀ ↽ − H 2 O ( l ) + Ba 2 + ( aq ) + Cl − ( aq ) Calculate the concentration of Ba ( OH ) 2 in the original 20.00 mL solution. [ Ba ( OH ) 2 ] = M Calculate the concentrations of Ba 2 + and Cl − in solution following the neutralization reaction.

Answers: 2

Show answers

Answers

Answer from: habsofarah0

The concentration of $Ba^{2+}\text{ and }Cl^-$ ions in the solution are 0.0426 M and 0.0852 M respectively

Explanation:

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

The chemical equation for the reaction of HCl and barium hydroxide follows:

$2HCl(aq.)+Ba(OH)_2(aq.)\rightarrow BaCl_2(s)+2H_2O(l)$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is Ba(OH)_2

We are given:

$n_1=1\\M_1=?M\\V_1=20.00mL\\n_2=2\\M_2=0.1255M\\V_2=42.50mL$

Putting values in above equation, we get:

$1\times M_1\times 20.00=1\times 0.1255\times 42.50\\\\M_1=\frac{1\times 0.1255\times 42.50}{1\times 20.00}=0.267M$

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$ .....(1)

Molarity of HCl solution = 0.1255 M

Volume of solution = 42.50 mL = 0.04250 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

$0.1255M=\frac{\text{Moles of HCl}}{0.04250L}\\\\\text{Moles of HCl}=(0.1255mol/L\times 0.04250L)=5.33\times 10^{-3}mol$

By Stoichiometry of the reaction:

2 moles of HCl produces 1 mole of barium chloride

So, $5.33\times 10^{-3}mol$ of HCl will produce = $\frac{1}{2}\times 5.33\times 10^{-3}mol=2.665\times 10^{-3}mol$

Calculating the concentration of barium chloride by using equation 1:

Moles of barium chloride = $2.665\times 10^{-3}mol$

Volume of solution = [20.00 + 42.50] mL = 62.5 mL = 0.0625 L

Putting values in equation 1, we get:

$\text{Molarity of barium chloride}=\frac{2.665\times 10^{-3}}{0.0625}=0.0426M$

1 mole of barium chloride produces 1 mole of barium ions and 2 moles of chloride ions

So, concentration of barium ions = 0.0426 M

Concentration of chloride ions = (2 × 0.0426) = 0.0852 M

Hence, the concentration of $Ba^{2+}\text{ and }Cl^-$ ions in the solution are 0.0426 M and 0.0852 M respectively

Answer from: Quest

each column of the table is called a group. elements in a group share similar properties. groups are read from top to bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o. 2. 3. 4. 5. 6. 7. 8. 9. 2. beryllium. 9.012. 4. sodium. 22.990. 11. 3. magnesium. 24.305. 12. potassium. 39.098. 19. 4. calcium. 40.078. 20. i guess i

Answer from: Quest

Must be negative.substance increases

Another question on Chemistry

Chemistry, 21.06.2019 17:50

An aqueous solution of potassium hydroxide is standardized by titration with a 0.194 m solution of hydrobromic acid. if 25.2 ml of base are required to neutralize 24.2 ml of the acid, what is the molarity of the potassium hydroxide solution? m potassium hydroxide

Answers: 2

Answer

Chemistry, 22.06.2019 09:00

What term is missing from the central region that describes hypotheses, theories, and laws? popular predictable mathematical falsifiable

Answers: 2

Answer

Chemistry, 22.06.2019 10:00

What is the atomic mass of an atom that has 6 protons, 6 neutrons, and 6 electrons? a) 6 b) 8 c) + 1 d) 12 e) 18

Answers: 1

Answer

Chemistry, 22.06.2019 20:00

Which of the following would not diffuse through the plasma membrane by means of simple diffusion? 1 oxygen 2 glucose 3 a steroid hormone 4 a lipid soluble vitamin

Answers: 3

Answer

You know the right answer?

A 20.00 mL Ba ( OH ) 2 solution of unknown concentration was neutralized by the addition of 42.50 mL...

Questions