Chlorine gas reacts with phosphorus to produce phosphorus pentachloride. How many grams of PCl5 are produced from 3.5 g of Cl2 and excess P? Cl2(g) + P(s) --> PCl5(s) ( unbalanced)

Therefore, 4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.

Explanation:

Given equation is ,

Cl₂(g)+P(s) ⇒PCl₅(s)

First we have to balance this equation

5Cl₂(g)+2P(s) ⇒2PCl₅(s)

The atomic mass of Cl = 35.435 grams

The atomic mass of P =30.97 grams

The mass of 5Cl₂=(5×2×35.435) gram =354.35 grams

The mass of 2PCl₅ =2{30.97+(5×35.435)}  gram = 416.29 grams

Therefore,

354.45 grams of Cl₂ needs to make 416.29 gram of PCl₅

1 gram of Cl₂ needs to make gram of PCl₅

3.5 grams of Cl₂ needs to make gram of PCl₅

                                                  =4.11 grams

Therefore, 4.11 grams of PCl₅ are produced from 3.5 gram of Cl₂ and excess P.

i do not get it   at all