How much energy is needed to heat a 35.5g sample of ice at -17.5°C to liquid water at
77.3°C

Q = 6831.8 J

Explanation: To solve for Q we will use the heat capacity formula:

Q= mc∆T, where the specific heat capacity of ice is ( c= 2.03 J / g°C ).

Q= 35.5 g ( 2.03 J / g°C) ( 77.3°C - (-17.5°C) )

Q= 72.065 J/ °C ( 94.8 °C)

Q= 6831.8 J

out of these options:

ability to burn paper

pure sodium reacting violently with water

the boiling point of water

helium does not tend to react with anything

i would say this is a physical property:

helium does not tend to react with anything

why? :

i said helium does not tend to react with anything because well, it reacts to ! but ability to burn paper, pure sodium reacting violently with water, & the boiling point of water are chemical or

physical properties: the properties of a substance that can be observed without changing the chemical makeup of the substance

chemical properties: properties of a substance relating to the chemical nature and reactivity of the substance