PROBLEMS
A 10.00 gram sample of a mixture of potassium bromide (KBr) and sand was obtained.
Water was added to the mixture to dissolve the KBr as KBr is soluble in water. When the
sand was filtered and dried, it was found to weigh 3.595 g. Assume that no sand was lost
during the experimental process and that the sand was completely dried. Determine the
percentages of sand and KBr in the original sample. Show your calculations clearly.
% sand:
Calculation:

% Mass of sand = 35.95%

% Mass of KBr = 64.05%

Explanation:

From the question given, we obtained the following:

Mass of mixture( KBr + sand) = 10g

Mass of sand = 3.595g

Mass of KBr = 10 — 3.595 = 6.405g

% Mass of sand = ( Mass of sand / mass of mixture) x 100

% Mass of sand = (3.595 / 10) x100

% Mass of sand = 35.95%

We can obtain the percentage of KBr by subtracting the percentage of sand from 100. This is illustrated below:

% Mass of KBr = 100 — 35.95

% Mass of KBr = 64.05%

sry but any answer choices

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.