How do I balance the redox equation
1) mno4- + I-beam + H+> MN 2+ +I2 +H2O

2MNO4 + 10 I- + 16 H+ → 5 I2 + 2 Mn 2+ + 8 H20

Explanation:

2 MnVII + 10 e- → 2 MnII ( reduction reaction)

10 I-I - 10 e- → 10 I°  (oxidation)

MnO4- is an oxidizing agent, I- is a reducing agent.

This is a redox reaction. A redox reaction can be described as a reaction in which oxidation as well as reduction are taking place. One of the atoms is being reduced while the other one is being oxidized.

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answer; i believe that the correct answer is (a) potassium(k)