What is the formula of the compound between calcium and sulfur that has the percent composition 55.6% calcium and 44.4% sulfur

The empirical formula is .

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of Ca = 55.6 g

Mass of S= 44.4 g

Step 1 : convert given masses into moles.

Moles of Ca=

Moles of S = \frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{44.4g}{32g/mole}=1.39moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Ca =

For S =

The ratio of Ca:S = 1:1

Hence the empirical formula is .

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