The pressure of 6.0 L of a gas is 200 kPA. What will be the volume of the pressure is doubled, keeping the temperature constant?

3. 0 L

Explanation:

We’ll use  P₁V₁/T₁ = P₂V₂/T₂

Because T₁ and T₂ are constant throughout, then the two cancel out and we are left with;

P₁V₁ = P₂V₂

We can bow replace the variables with given values form the question;

200 * 6.0 = 400 * V₂

200 * 6 / 400 = V₂

3 = V₂

= 3.0 L

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: