Calculate the number of moles of solute present in 55.0 mg of an aqueous solution that is 1.45 m NaCl. Assume that for dilute aqueous solutions, the mass of the solvent is the mass of solution.

0.00007975 mole

Explanation:

Number of moles can be calculated as; mass of solute/volume of solvent or concentration of solution x volume of that solution.

In this case:

Concentration of solution = 1.45 M

Mass of solvent (water in this case) = 55.0 mg

55.0 mg of water is equivalent to 0.55 ml of water.

Therefore, volume of solution = 0.055 ml

Hence, number of moles of solute = molarity x volume

                                                           1.45 x 0.000055 = 0.00007975 mole

if the concentration of products is decreased, the equilibrium will shift toward the products). add an inert gas (one that is not involved in the reaction) to the constant-volume reaction mixture: this will increase the total pressure of the system, but will have no effect on the equilibrium condition.

explanation:

answer: they produce more slow than unicellular organisms.