At a certain temperature, Kp for the reaction, Cl2(g) + Br2(g) <=> 2 BrCl(g) is 0.00029. Calculate the value of Kp for the reaction, BrCl(g) <=> 1/2 Cl2(g) + 1/2 Br2(g)

Kp = 59

Explanation:

For the reaction:

Cl₂(g) + Br₂(g) ⇄ 2BrCl(g) Kp = 0,00029

The k of the reciprocal reaction is:

2BrCl(g) ⇄ Cl₂(g) + Br₂(g) Kp = 1/0,00029 = 3448

As the kp of the reaction that we need to calculate is the half of the last reaction, that is:

BrCl(g) ⇄ ¹/₂Cl₂(g) + ¹/₂Br₂(g) Kp is √3448 = 59

I hope it helps!

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

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