If methyl benzoate is the limiting reagent, and 1.3 g of methyl benzoate were used for this reaction, what is the theoretical yield of the mono nitration reaction? (hint: the product formula is C8H7O4N)

The theoretical yield is 1.73 grams

Explanation:

Step 1: Data given

Mass of methyl benzoate =  1.3 grams

Molar mass methyl benzoate = 136.15 g/mol

methyl benzoate = C8H8O2

Step 2: The balanced equation

C8H8O2 + HNO3 → C8H7O4N + H2O

Step 3: Calculate moles methyl benzoate

Moles methyl benzoate = mass / molar mass

Moles methyl benzoate = 1.3 grams / 136.15 grams

Moles methyl benzoate = 0.00955 moles

Step 4: Calculate moles C8H7O4N

For 1 mol methyl benzoate we need 1 mol HNO3 to produce 1 mol C8H7O4N and 1 mol H2O

For 0.00955 moles methyl benzoate we'll have 0.00955 moles C8H7O4N

Step 5: Calculate mass C8H7O4N

Mass C8H7O4N = moles * molar mass

Mass C8H7O4N = 0.00955 moles * 181.1455 g/mol

Mass C8H7O4N = 1.73 grams

The theoretical yield is 1.73 grams

2b2t

explanation:

2b2t

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.