QUESTION 21 The combustion of ammonia in the presence of excess oxygen yields NO 2 and H 2O: 4 NH 3 (g) 7 O 2 (g) 4 NO 2 (g) 6 H 2O (g) The combustion of 14.4 g of ammonia consumes g of oxygen.

The answer to your question is 47.44 g of Oxygen

Explanation:

Data

mass of Ammonia = 14.4 g

mass of Oxygen = ?

Balanced chemical reaction

                 4NH₃  +  7O₂  ⇒  4NO₂  +  6H₂O

Process

1.- Calculate the molar mass of Ammonia

NH₃ = 4[(1 x 14) + (3 x 1)] = 4[14 + 3] = 4[17] = 68 g

2.- Calculate the molar mass of Oxygen

O₂ = 7[16 x 2] = 7[32] = 224 g

3.- Use proportions to calculate the mass of Oxygen

                     68g of NH₃ 224 g of O₂

                      14.4 g of NH₃  x

                       x = (14.4 x 224) / 68

                       x = 3225.6/ 68

                       x = 47.44 g

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