C6H5NH3Cl is a chloride salt with an acidic cation. If 46.3 g of C6H5NH3Cl is dissolved in water to make 150 mL of solution, what is the initial molarity of the cation

The initial molarity of cation is 2.38 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of = 46.3 g

Molar mass of =  129.6 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

1 mole of produces 1 mole of cation and 1 mole of anion

So, molarity of cation = (1 × 2.38) = 2.38 M

Hence, the initial molarity of cation is 2.38 M

i need mutiple choices

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8