Calculate the change in enthalpy for the reaction, given the associated enthalpies of formation. 2NO(g)+O2(g)⟶2NO2(g)ΔHf, NO2=33.2 kJΔHf, NO=90.2 kJ Round the answer to three significant figures.

where is the following

explanation:

when [oh-] is 10-5  m, and [h3o+] is 10-9  m, the poh is 5 and ph is 9. again in both cases the sum of ph and poh is 14. however, the hydrogen ion concentration is not always going to be equal to exactly 1 x 10 raised to a negative number. for example, we skipped over the value of 2.0 x 10-7.

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