In Chem 1B your final course grade is made up of 60% of your lecture grade and 40% of your lab grade. Your lab grade is composed of your report sheets, lab exams and seminar quizzes. Your lecture grade is composed of your lecture exams, final exams and quizzes (in class or through Canvas, as determined by the course lecturer).

Go look in the Chem 1B Lab Greensheet for the weight of each graded component for lab (35% report sheets, 35% lab exams, 30% lab quizzes). A student is trying to figure out his LAB percent. So far he has 86% in report sheets, 66% in the lab exam and 76% in quizzes. What is the students total lab % at this time rounded to two digits?

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.