The partial pressures of the gases when at equilibrium are found to be: A: 6.70 atm, B: 10.1 atm, C: 3.60 atm. Evaluate Kp for this reaction. 2A(g) B(g) --> C(g)

Answer : The value of equilibrium constant (Kp) is,

Explanation :  Given,

Partial pressure of A at equilibrium = 6.70 atm

Partial pressure of B at equilibrium = 10.1 atm

Partial pressure of C at equilibrium = 3.60 atm

The given chemical reaction is:

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:

Thus, the value of equilibrium constant (Kp) is,

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