A solution is made by mixing of 51 g of heptane and of acetyl bromide . Calculate the mole fraction of heptane in this solution. Round your answer to significant digits.

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A solution is made by mixing of 51 g of heptane and 127 g of acetyl bromide. Calculate the mole fraction of heptane in this solution. Round your answer to 3 significant digits.

The mole fraction of heptane in the solution is 0.330

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of heptane = 51 g

Molar mass of heptane = 100.2 g/mol

Putting values in equation 1, we get:

Given mass of acetyl bromide = 127 g

Molar mass of acetyl bromide = 123 g/mol

Putting values in equation 1, we get:

Mole fraction of a substance is given by:

Moles of heptane = 0.509 moles

Total moles = [0.509 + 1.032] = 1.541 moles

Putting values in above equation, we get:

Hence, the mole fraction of heptane in the solution is 0.330