Given a diprotic acid, H 2 A , with two ionization constants of K a1 = 4.8 × 10 − 4 and K a2 = 3.6 × 10 − 12 , calculate the pH for a 0.126 M solution of NaHA.

answer:

the answer is 6 valence electrons.

explanation:

valence is the # of electrons on the outer most shell of an atom.

oxygen has 6.

although, the valency of oxygen is 2, because it only needs to make 2 covalent bonds, or gain 2 electrons, to achieve the stable octet configuration of a noble gas.

that's it!

if you need further assistance, let me know: )

~ trueboss72